Question

Fie MON NOP POM unghiuri in jurul punctului O,astfel in cat m(MON)=2x+50° m(NOP)=6x si m(POM)=x+40°​

Answer 1

Explicație pas cu pas:

1.m(MON)=2x+50°

4•(0x)-2+50°m

4•0-2+50°m

4•0-2+1m=>4•0-2+m=>0•2+m

SOLUTIE→-2+m

2.m(NOP)=6x

m•MOP=6x=>m²OP=6x

6x=m²OP=>x=1/6m²OP

SOLUTIE→x=1/6m²OP;MER, OER, PER.

3.m(POM)=x+40°

mPOM=x+40°=>m²PO=x+40°

-x+m²PO=40°=>-x=40°-m²PO

x=-40°+m²PO

SOLUTIE→x=-40°+m²PO,MER,PER,OER.

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