Question

Fie numerele naturale consecutive impare a, b si c.stiind ca a<b<c iar b+c=16 calculati axb+axc

Answer 1

b+c=16 x+x+2=16 2x=14 x=7 ⇒b=7;c=9;a=5 a*b+a*c=5*7+5*9 =35+45 =80