Question

Fie numerele naturale nenule x=p2+p,y=p-1,z=p^2-1.Calculand x·y/z,vei obtine:

Answer 1

x=p²+p
y=p-1
z=p²-1

x*y/z=
=$\frac{ (p^{2}+ p)(p-1)}{ p^{2} -1}$=

= $\frac{p(p+1)(p-1)}{ p^{2} -1}$=

=$\frac{p( p^{2} -1)}{ p^{2} -1}$ =

=p