Question

Fie triunghiul ABC,m(A)=90° si AD paralel BC D apartine(BC).AD=6cm si CD=8cm,calculati BD, BC, AB, AC

Answer 1

AC^2 =AD^2+DC^2
AC^2 =6^2+8^2
AC^2 =36+64 =100
AC =10 cm

AC^2 =BC*DC
10^2 =BC*8
BC =100:8 =12.5 cm

BD =BC-DC
BD =12.5-8 =4.5 cm

AB^2 =BC^2-AC^2
AB^2 =12.5 ^2-10^2
AB^2 =156.25-100 =56.25
AB =7.5 cm