Question

Fie x=(2^7)^5 x (2^10)^14 : (2^3)^5
Scrieti x ca putere a lui 2 si aratati ca x este patrat perfect

Answer 1

• (2^7)^5=2^7×5=2^35
• (2^10)^14=2^140
• (2^3)^5=2^3×5=2^15

x=2^35×2^140:2^15=2^35+140-15=2^160

x=2^160=(2^80)^2

x=(2^80)^2

• După urmare x pătrat perfect

Answer 2

(2^7)^5 = 2^7×5 = 2^35

(2^10)^14 = 2^10×14 = 2^140

(2^3)^5 = 2^3×5 = 2^15

x = 2^35 × 2^140 : 2^15 = 2^35+140-15 = 2^160

x = 2^160 = (2^80)^2

x = (2^80)^2 prin urmare x este patrat perfect