Question

fie x=rad6+1siy=rad2+rad3.calculati valoarea expresei(x^2-y^2-2)^2007

Answer 1

x²-y²-2=(√6+1)²-(√2+√3)²-2=6+2√6+1-(2+2√6+3)-2=7+2√6-5-2√6-2=7-5-2=0
(x²-y²-2)²⁰⁰⁷=0²⁰⁰⁷=0

Answer 2

x=√6+1       x²=6+2√6+1=7+2√6
y=√2+√3     y²=2+2√6+3=5+2√6
(x²-y²-2)²⁰⁰⁷=[7+2√6-(5+2√6)-2]²⁰⁰⁷=(7+2√6-5-2√6-2]²⁰⁰⁷=(0)²⁰⁰⁷=0