Question

folosind formule de calcul prescurtat calculeaza (√6x-3)²(√6x+√3)²

Answer 1

Bună!

$(\sqrt{6} x-\sqrt{3} )^{2} (\sqrt{6} x+\sqrt{3} )^{2} = [(\sqrt{6}x-\sqrt{3} )*(\sqrt{6}x +\sqrt{3} )]^{2} = [(\sqrt{6}x)^{2} -\sqrt{3} ^{2}] =(6x^{2} -3)^{2} =36x^{4} -36x^{2} +9$

Formule folosite:

(a-b)(a+b)= a²-b²

(a-b)²=a²-2ab+b²