Question

Folosind reguli de calcul cu puteri, calculați:
a) 7×7^23:7^24
b) 11^50-11×11^49
c) 2^17×2^18-2^34×2
d) (29-2×7)^2×15^20-15^22
e) (12-3)^2×(6+3)^18-9^20
f) (4^2:2^2)^2×4^18:256^5​

Answer 1

Răspuns:

Explicație pas cu pas:

a) 7×7^23:7^24 =7^(23+1):7^24=7^24:7^24=1

b) 11^50-11×11^49 =11^50-11^(49+1)=11^50-11^50=0

c) 2^17×2^18-2^34×2 =2^(17+18)-2^(34+1)=2^35-2^35=0

d) (29-2×7)^2×15^20-15^22 =(29-14)²×15^20-15^22=15^(2+20)-15^22=0

e) (12-3)^2×(6+3)^18-9^20 =9²×9^18-9^20=9^(2+18)-9^20=0

f) (4^2:2^2)^2×4^18:256^5​=2^4×2^36:2^(8·5)=2^40:2^40=1