Question

Folosind reguli de calcul cu puteri , calculati :
a)7*7 la puterea 23 : 7 la puterea 24
b)11 la puterea 50 -11*11 la puterea 49
c)2 la puterea 17* 2 la puterea 18 - 2 la puterea 34* 2
d)( 29 -2*7 )totul la puterea 2*15 la putera 20-15 la puterea 22
e)(12-3)la puterea 2*(6+3)la puterea 18 -9 la puterea 20
f) (4 la puterea 2 : 2 la puterea 2 ) totul la 2* 4 la puterea 18 : 256 la puterea 5
Va rog repede!!!!

Answer 1

$a).7*7^2^3:7^2^4=7^1^+^2^3:7^2^4=7^2^4:7^2^4=1 \\ \\ b).11^5^0-11*11^4^9=11^5^0-11^{1+49}=11^5^0-11^5^0=0 \\ \\ c).2^1^7*2^1^8-2^3^4*2=2^{17+18}-2^{34+1}=2^3^5-2^3^5=0 \\ \\ d).(29-2*7)^2*15^2^0-15^2^2=(29-14)^2*15^2^0-15^2^2= \\ \\ =15^2*15^2^0-15^2^2=15^{2+20}-15^2^2=15^2^2-15^2^2=0$

$e).(12-3)^2*(6+3)^1^8-9^2^0=9^2*9^1^8-9^2^0=9^{2+18}-9^2^0= \\ \\ =9^2^0-9^2^0=0 \\ \\ f).(4^2:2^2)^2*4^1^8:256^5=[(4:2)^2]^2*(2^2)^1^8:(2^8)^5=2^4*2^3^6:2^4^0= \\ \\ =2^{4+36}:2^4^0=2^4^0:2^4^0=1$