Question

Formula lui gauss:a)s=1+2+3+41.....+203, s=1+2+3+47......+407, s=1+2+3+.....+2007, s=5+10+15+......1005, s=2+4+6+......+1202, s=1+3+5+......219.va rog dau coroana

Answer 1

Ff simplu formula n(n+1):2 neste ultimul nr si inlocuim n=203 203×204÷2=203×102===.... asa faci si la celelalte..