Question

Formula procentuală a apei oxigenate???

Answer 1

Ai vrut sa scrii compozitia procentuala  a apei oxigenate

se calculeaza masa molara

M H2O2=2+ 2.16= 34-----> 1mol=34 g [ 34g/moli ]

34 g H2O2 ---------2g H-----------32g O

100g------------------x---------------------y

x= 100.2: 34=5,88 % H

y=100.32 : 34=94,11 % O

Answer 2

H202 apa oxigenata

Masa H202=1+1+16+16=34
34g H202........2gH
100g H202....X
X=100*2/34=5,88% Hidrogen

34g H202......32g0
10g H202.....Y
Y=100*32/34=94,11% Oxigen

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