Question

FUNCTII CLASA 10 VA ROG AJUTOR​

Answer 1

Răspuns:

a)f(x)= -2x+3

y=-2x+3

y-3=-2x

x=(y-3)/(-2)

f(y)= y/(-2)+3/2

SE trece la variabila   x

f⁻⁻¹(x)=-x/2+3/2

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b) f(x)=x/2-1

y=x/2-1

x/2=y+1

x=2y+2

f(y)=2y+2)

f⁻¹(x)=2x+2

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c)f(x)=3x-5

y=3x-5

y+5=3x

x=(y+5)/3

f(y)=(y+5)/3

f⁻¹(x)=(x+5)/3

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d) f(x)= -x/4-2

y= -x/4-2

y+2= -x/4

x=-4y-8

f⁻¹(x)= -4x-8

--------------------------grafic

f⁻¹(x)=-x/2+3/2

f⁻¹(x)=0

-x/2+3=0

-x/2= -3

x=6 B(6,0)

f⁻¹(0)=-0/2+3=3

C(0,3) Gf⁻¹= BC

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f⁻¹(x)=2x+2

f⁻¹(x)=0

2x+2=0

2x= -2

x= -1

D(-1,0)

f⁻⁻¹(0)=2

E(0,2)\

Gf⁻⁻¹=¹DE

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c.f⁻¹(x)=(x+5)/3

f⁻⁻¹(x)=(x+5)/3=0

x= -5) F(-5,0)

f⁻¹(0)=5/3 G(0,5/3)

Gf⁻¹=(FG)

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d)f⁻¹(x)= -4x-8

f⁻¹(x)=0

-4x-8=0

-4x=8

x=2

H(2,0)

f⁻¹(0)= -8

I(0,-8)

ATasez imediat si graficele

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