Question

gaseste numerele pentru care: aaa+bbb=777 aab+bba=333 aba+bab=888

Answer 1

aaa+bbb=777 <=> 111+666 = 777 ; 222+555=777 ; 333+444 = 777 ;

444+333 = 777 ; 555+222=777 ; 666+111 = 777

aab+bba=333 <=> 110 x a +110 x b + a + b = 333 <=>

111 x a + 111 x b = 333 <=> 111(a+b) = 333=> a+b = 3 => a = 1 ; b = 2 ; a=2 ;b=1

Adica : 112+221 = 333 si 221+112 = 333

aba+bab=888

100a+10b+a+100b+10a+b=888 <=> 111a + 111b = 888 <=> 111(a+b) = 888 =>

a+b = 8 => a=1 ; b=7 ; a=2 ; b=6 ; a=3; b=5 ; a=5 ; b = 3 ; a=6 ; b=2 ; a=7 ; b=1

Adica: 171+717 = 888 ; 262+626 = 888 ; 353+535=888 ; 535+353=888 ;

626+262=888 ; 717+171 = 888