Question

Gaseste valoarea lui "a" si verifica apoi rezultatul gasit:

40x{26-2x[10+(a+2)]}=0

Answer 1

26-2×[10+(a+2)]=0:40
2×[10+(a+2)]=26-0
10+(a+2)=26:2
a+2=13-10
a=3-2
a=1
Verificare:
40×E26-2×[10+(1+2)]E=
40×[26-2×(10+3)]=
40×(26-2×13)=
40×(26-26)=
40×0=0

Answer 2

40 x { 26 - 2x [ 10 + ( a +2 )]}= 0
26 - 2x [ 10 + ( a + 2 )] = 0 : 40
26 - 2x [ 10 + ( a + 2 )] = 0
2x [ 10 + ( a + 2 ) ] = 0 + 26
2x [ 10 + ( a + 2 ) ] = 26
10 + ( a + 2 ) = 26 : 2
10 + ( a + 2 ) = 13
a + 2 = 13 - 10
a + 2 = 3
a = 3 - 2
a = 1
verificam
40 x ( 26 - 2x [ 10 + ( 1 + 2 )]}=
40 x { 26 - 2x [ 10 + 3 ] =
40 x [ 26 - 2 x 13 ]=
40 x ( 26 - 26 )=
40 x 0 = 0