Question

Gasiti perechii de nr nat mai micidecat 10 pentru care sa fie adevarate egalitatiile.a) (a+3)×(b+2)=24;(a+2)×(b-3)=36;(a-l)×(b-2)=2;(a-l)×(b+2)=18

Answer 1

1. (1+3)×(4+2)=24
2.(4+2)×(9-3)=36
3. (2-1)×(4-2)=2
4. (2-1)×(16+2)=18