Question

gasiti prin substitutie,ecuatiile care au solutia 1)4 2)10 a)3+x=28:4 b)59(x+2)=32 c)2a-3=17 d)120:z=12 e)8y+6=42-4 f)20+3t=100:2

Answer 1

ecuatia punctului a are sulutia 4
deoarece 3+4=28:4
3+4=7
28:4=7

ecuatia punctului c are solutia 10
deoarece 2x10-3=17
2x10=20
20-3=17

ecuatia punctului f are solutia 10
deoarece 20+3x10=100:2
3x10=30
20+30=50
100:2=50