Question

gasiti toate numerele de forma abc astfel ancat a=4 b+c=8.

Answer 1

a=4
b={0,1,2,3,5,6,7,8}
c={0,1,2,3,5,6,7,8}
b+c=8 ⇔0+8=8⇒abc=408;
b+c=8 ⇔1+7=8⇒abc=417;
b+c=8 ⇔2+6=8⇒abc=426;
b+c=8 ⇔3+5=8⇒abc=435;
b+c=8 ⇔8+0=8⇒abc=480;
b+c=8 ⇔7+1=8⇒abc=471;
b+c=8 ⇔6+2=8⇒abc=462;
b+c=8 ⇔5+3=8⇒abc=453;
b+c=8 ⇔4+4=8⇒abc=444;nu corespunde nr abc pentru ca  toate cifrele sunt egale, iar nr are cifre diferite

Answer 2

$\frac{}{abc}$ = [tex]\frac{}{408}, \frac{}{417}, \frac{}{426}, \frac{}{435}, \frac{}{453}, \frac{}{462}, \frac{}{471}, \frac{}{480}.[/tex]