Question

Gasiti trei numere naturale a,b,c pentru care $x^{3}+7 x^{2} +14x+8=(x+a)ori(x+b)ori(x+c)$

Answer 1

Se observa -1 radacina
$x^{3} +7 x^{2} +14x+8= x^{3} +x^{2} +6 x^{2} +6x+8x+8$
$=(x+1)( x^{2} +6x+8)=(x+1)( x^{2} +4x+2x+8)$
$=(x+1)(x+2)(x+4)_$