Question

gazul metan dintr-un cilindru de otel exercita la 57 grade presiune de 3 atm ....Ce presiune va crea in cilindtu la temp de 227grade?

Answer 1

t1 = 57 °C => T1= 57+ 273 = 330 K
t2= 227 °C => T2 = 227 + 273 = 500 K
p1= 3 atm
p2=?
V= constant

$\frac{p_1}{T_1} = \frac{p_2}{T_2}$
 ⇒ $p_{2} = \frac{p_1 * T_2 }{T_1}$
$p_{2} = \frac{3*500}{330}$ = 4.55 atm