Question

h)(32 18-10 (105-54:a): 11-36:9+40:8 = 7
3) Află numărul necunoscut:
a) 232 +[48 * 25+(540 xa-82 *5) * 10]: 100 = 797
90
of
200​

Answer 1

Răspuns:

[32x18-10x(105-54:a)]:11-36:9+40:8=7

[576-10x(105-54:a)]:11-4+5=7

[576-10x(105-54:a)]:11-4=7-5

[576-10x(105-54:a)]:11-4=2

[576-10x(105-54:a)]:11=2+4

[576-10x(105-54:a)]:11=6

[576-10x(105-54:a)]=6x11

576-10x(105-54:a)=66

10x(105-54:a)=576-66

10x(105-54:a)=510

(105-54:a)=510:10

105-54:a=51

54:a=105-51

54:a=54

a=54:54

a=1

232+[48x25+(540xa-82x5)x10]:100=797

[1200+(540xa-410)x10]:100=797-232

[1200+(540xa-410)x10]:100=565

[1200+(540xa-410)x10]=565x100

1200+(540xa-410)x10=56500

(540xa-410)x10=56500-1200

(540xa-410)x10=55300

(540xa-410)=55300:10

540xa-410=5530

540xa=5530+410

540xa=5940

a=5940:540

a=11