Question

Hei ,care imi face B si C ,dau coroana va rog!!

Answer 1

b)
[(4-√3)/√3+(2√3-3)/√12]×(2/√6+3√6/2-12√2/4√3)=
=(4/√3-1+1-3/√12)×(2/√6+3√6/2-3√2/√3)=
=(4/√3-3/2√3)×(2√6+9√6-6√6)/6=
=(8√3-3√3)/6×5√6/6=
=5√3/6×5√6/6=
=25√18/36=
=75√2/36=
=25√2/12


c)(5/3√5-√5/10+4/√45):(3√10+1/3√10-62/6√10)=
=(5√5/15-√5/10+4/3√5):(3√10+√10/30-62√10/60)=
=(5√5/15-√5/10+4√5/15):(3√10+√10/30-62√10/60)=
=(9√5/15-√5/10):(180√10+2√10-62√10)/60=
=(3√5/5-√5/10):120√10/60=
=(6√5-√5)/10  :2√10=
=5√5/10 ×1/2√10=
=√5/2 ×1/2√10=
=1/4√2=
=√2/8