Question

Help,dau coroana!!
Cantitatea de sulf continuta in 3 moli de sulfat de aluminiu e:
a)288g b)144g c)28,8g d)232g
indicatii: 1)aplicati formula pentru masa molara si aflati m de sulfat Al
2)Calculati M si aflati sulful

Answer 1

$M_{Al2(SO4)3}$ = 2*27+3*32+3*4*16 = 54+96+192= 342 g/mol

In 1 mol Al2(SO4)3............................ 3*32=96g S

In 3 moli Al2(SO4)3........................... x g S

x=3*96= 288g => a) 288g