Question

Help me pls :)).....

Answer 1

$2*2^{1}*2^{2}...*2^{10}=2^{1+2+3+...+10}=2^{55}=(2^{5})^{11}=32^{11}$

$1+2+3+...+10=\frac{10(10+1)}{2}=\frac{10*11}{2}=5*11=55$


$3^{44}=(3^{4})^{11}=81^{11}$


$32^{11}<81^{11} => 2*2^{1}*2^{2}...*2^{10} < 3^{44}$