Question

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Answer 1

$6.\ 2^{0}=1\\2^{2}=4\\2^{5}=32\\2^{3}=8\\2^{4}=16\\4^{3}=(2^{2})^{3}=2^{6}\\16^{2}=(2^{4})^{2}=2^{8}\\7.\ 3^{0}=1\\3^{1}=3\\3^{4}=81\\3^{2}=9\\3^{3}=27\\27=(3^{3})^{3}=3^{9}\\81^{2}=(3^{4})^{2}=3^{8}\\9^{4}=(3^{2})^{4}=3^{8}\\27^{3}=(3^{3})^{3}=3^{9}\\8.\ 5=5^{1}\\1=5^{0}\\25^{4}=(5^{2})^{4}=5^{8}\\125=5^{3}\\625=25^{2}=(5^{2})^{2}=5^{4}\\125^{2}=(5^{3})^{2}=5^6$