Question

Hey am si eu o problema:((    Fie triunghiul ABC cu m(<B)=90grade,m(<C)=30si AC=14cm.Prin punctul M apartine lui AC se duce paralela MN la BC ,N apartine lui AB .Daca AM=6cm,aflati lungimile segmentelorAB,MC AN si NB 

Answer 1

sin 30 = $\frac{AB}{AC}$
$\frac{1}{2}$ = $\frac{AB}{14}$
AB=7 cm

MC=AC - AM
MC=14-6
MC=12 cm

$\frac{AN}{AB}$ = $\frac{AM}{AC}$ (Teorema fundamentala a asemanarii)
$\frac{AN}{7}$ = $\frac{6}{14}$
AN=3 cm

NB=AB-AN
NB=7-3
NB=4 cm