Question

I.Se ard 0,6 moli de fier. Determina masa de oxid de fier(II) formata in reactie.
Reactia chimica este:
Fier + Oxigen  Oxid de fier
Mase atomice : O-16 ; Fe-56

Answer 1

Răspuns:

MFe=56g/mol

MFeO=56+16=72g/mol

m=0,6×56=33,6g

2×56g 2×72g

2Fe + O2 => 2FeO

33,6g yg

y= 33,6××72/2×56= calculează