Question

identifica nr b si c,stiind ca a=1624,1/4 din b este mai mic decat 1/4 din c cu 29,iar a+3b+2c=4496

Answer 1

a=1624
b/4=c/4-29
a+3b+2c=4496
b=c-29x4
b=c-116
c=b+116

1624+3b+2(b+116)=4496
1624+3b+2b+232=4496
5b=4496-1624-232
5b=2872-232
5b=2640
b=2640:5
b=528

c=b+116
c=528+116
c=644

Verificare:a+3b+2c=4496
1624+3x528+2x644=1624+1584+1288=3208+1288=4496