Question

Îmi poate rezolva și mie problemă vă rog

Answer 1

Răspuns:

Explicație pas cu pas:

$\textrm{a)}\\\\ \Bigg(\Big(\frac{9}{28} + \frac{1}{7}\Big)+\Big(\frac{4}{7}-\frac{1}{28}\Big)\Bigg)\cdot 7\\\\ = \Bigg(\Big(\frac{9}{28} + \frac{4}{28}\Big)+\Big(\frac{16}{28}-\frac{1}{28}\Big)\Bigg)\cdot 7\\\\ = \Bigg(\frac{13}{28}+\frac{15}{28}\Bigg)\cdot 7\\\\ = \frac{28}{28}\cdot 7 = 7$

$\textrm{b)}\\\\19 - \frac{11}{2}\div \frac{33}{2} + 3^{-1}\\\\ = 19 - \frac{11}{2}\cdot \frac{2}{33} + \frac{1}{3}\\\\= 19 - \frac{1}{3} + \frac{1}{3}\\\\ = 19$

$\textrm{c)}\\\\\Bigg(\frac{2}{5} - \Big(\frac{-3}{4}\Big)\div\frac{7}{4} \Bigg)\cdot 1\frac{6}{29}\\\\=\Bigg(\frac{2}{5} + \frac{3}{4}\cdot\frac{4}{7} \Bigg)\cdot \frac{35}{29}\\\\=\Bigg(\frac{2}{5} + \frac{3}{7} \Bigg)\cdot \frac{35}{29}\\\\=\Bigg(\frac{14}{35} + \frac{15}{35} \Bigg)\cdot \frac{35}{29}\\\\ \frac{29}{35} \cdot \frac{35}{29} = 1$

$\textrm{d)}\\\\\Bigg(-\frac{1}{6}\cdot \frac{36}{5} - \frac{7}{6}\div \frac{7}{2}\Bigg) \div 1\frac{8}{15}\\\\=\Bigg(-\frac{6}{5} - \frac{7}{6}\cdot \frac{2}{7}\Bigg) \div \frac{23}{15}\\\\ = \Bigg(-\frac{6}{5} - \frac{1}{3}\Bigg) \cdot \frac{15}{23}\\\\ = \Bigg(-\frac{18}{15} - \frac{5}{15}\Bigg) \cdot \frac{15}{23}\\\\=-\frac{23}{15} \cdot \frac{15}{23} = -1$

Answer 2

Răspuns:

Explicație pas cu pas:

IV .

a )

[ ( 9/28 + ⁴) 1/7 ) + ( ⁴) 4/7 - 1/28 ) ] • 7 =

[ ( 9/28 + 4/28 ) + ( 16/28 - 1/28 ) ] • 7 =

( 13/28 + 15/28 ) • 7 =

28/28 (²⁸ • 7 =

1 • 7 = 7

b )

19 - 11/2 : 33/2 + 3-¹ =

19 - 11/2 • 2/33 + 1/3 =

19 - 1/3 + 1/3 = 19

c )

[ 2/5 - ( -3/4 ) : 7/4 ] • 1 6/29 =

[ 2/5 - ( -3/4 ) • 4/7 ] • 35/29 =

[ 2/5 - ( -3/7 ) ] • 35/29 =

( ⁷) 2/5 + ⁵) 3/7 ) • 35/29 =

( 14/35 + 15/35 ) • 35/29 =

29/35 • 35/29 = 1

d )

[ - 1/6 • 36/5 - 7/6 : 7/2 ] : 1 8/15 =

[ - 1 • 6/5 - 7/6 • 2/7 ] : 23/15 =

[ ³ ) - 6/5 -⁵ ) 1/3 ] • 15/23 =

[ - 18/15 - 5/15 ] • 15/23 =

-23/15 • 15/23 = -1