Question

imi trebuie URGENT !!!!​

Answer 1

$x + 1 \leqslant \sqrt{2} (x + 1)$

$x + 1 \leqslant \sqrt{2} x + \sqrt{2}$

$x - \sqrt{2}x \leqslant \sqrt{2} - 1$

$(1 - \sqrt{2} )x \leqslant \sqrt{2} - 1$

$x \geqslant \frac{ \sqrt{2} - 1 }{1 - \sqrt{2} }$

$x \geqslant \frac{ \sqrt{2} - 1 }{ - ( - 1 + \sqrt{2)} }$

$x \geqslant - 1$

x €[-1,+infinit)

Answer 2

Explicație pas cu pas:

4.

√(3x-1)²+√(2y+3)²=0

|3x-1|+|2y+3|=0

|3x-1|=0

x=1/3

|2y+3|=0

y=-3/2

Deci: x=1/3; y=-3/2

6.

xy=25

x-y=2√5 (²)

(x-y)²=20

x²-2xy+y²=20

x²+y²=20+2xy

x²+y²=20+2*25

x²+y²=70

Bafta!