Question

Imi trebuie urgent va rog!……..

Answer 1

,

$= > \sqrt{(x - 4 \sqrt{3}) ^{2} } = 0. \\ (x - 4 \sqrt{3}) ^{2} = 0 . \\ x - 4 \sqrt{3} = 0. \: \: \: x = 4 \sqrt{3} \\ \sqrt{(y - 2 \sqrt{3})^{2} } = 0 \\ (y - 2 \sqrt{3})^{2} = 0. \: \: \: y - 2 \sqrt{3} = 0. \\ y = 2 \sqrt{3} \\ \\ 1)x + y = 4 \sqrt{3} + 2 \sqrt{3} = \sqrt{3}(4 + 2) \\ = 6 \sqrt{3} \\ 2)x^{2} + y^{2} = (4 \sqrt{3}) ^{2} + (2 \sqrt{3})^{2} = \\ 16 \times 3 + 4 \times 3 = 48 + 12 = 60 \\ 3) \frac{x}{y} = \frac{4 \sqrt{3} }{2 \sqrt{3} } = 4 \div 2( \sqrt{3} \div \sqrt{3}) \\ = 2 \sqrt{3 \div 3} = 2 \sqrt{1} = 2 \times 1 = 2$

Salut! Sper ca te-am ajutat. Mi-a luat mult sa il fac.

Coroana? ;)