Question

imi trebuie urgenttt​

Answer 1

$x = \frac{1 \times 6 + 5}{6} = \frac{11}{6} = \frac{33}{18} \\ \\ y = \frac{1 \times 9 + 8}{9} = \frac{17}{9} = \frac{34}{18} \\ \\ \frac{33}{18} < \frac{34}{18} \\ \\ \implies a) \: \: x < y \\ \\ \\ \\ \\ \\ \\ \\ \\ b) \: \: y : (x {}^{2} - y) \\ \\ = \frac{17}{9} : \ [ ( \frac{11}{6}) {}^{2} - \frac{17}{9} \ ] \\ \\ = \frac{17}{9} : \frac{9 \times \frac{121}{36} - 17 }{9} \\ \\ = \frac{17}{9} : \frac{ \frac{121}{4} - 17 }{9} \\ \\ = \frac{17}{9} : \frac{ \frac{53}{4} }{9} \\ \\ = \frac{12}{\not9} \times \frac{\not36}{53} \\ \\ = \frac{68}{53}$