Question

impartind numarul 95 in parti invers proportionale cu 0,(6);3/4;0,8(3);4/5​

Answer 1

Răspuns:

(a,b,c,d)i.p(0,(6);0,75;0,8;0,8(3)

a+b+c+d=3804

a*6/9=b*75/100=c*8/10=d*75/90=k

a=9k/6=3k/2

b=100k/75=4k/3

c=10k/8=5k/4

d=90k/75=6k/5

3k/2+4k/3+5k/4+6k/5=3804

aducem la acelasi numitor, numitorul fiind 60

(90k+80k+75k+72k):60=3804

317k:60=3804

k=60*12

k=720

a=720*3/2=1080

b=4*720/3=960

c=5*720/4=900

d=6*72

Explicație pas cu pas:

Sper ca te-am ajutat