Question

Impartind suma a 6 nr naturale consecutive la 10,obtinem catul 12 ai restul 9.Sa se afle cele 6 numere

Answer 1

(a+a+1+a+2+a+3+a+4+a+5):10=12 si 9

(6a+15):10=12 si 9

(6a+15-9) :10=12

(6a+6):10=12

6a+6=120

6a=120-6

6a=114

a=114:6

a=19

Numerele sunt:19;20;21;22;23;24