Question

Impartiti nr 106 in parti direct proportionale cu nr 0,(3) ; 2 ; si 1,2.(raspuns + explicatie daca se poate va rog )

Answer 1

0,(3)=3/9=1/3
2
1,2

a=k/3
b=2k
c=1,2k
k/3+2k+1,2k=106
k+6k+3,6k=318
10,6k=318
k=30
a=k/3=30/3=10
b=2k=2×30=60
c=1,2k=1,2×30=36