Question

Impartiti nr 3804 in părți invers proporţionale cu 0,(6);0,75;0,8;0,8(3).​

Answer 1

3804 in parti invers proportionale cu 0,(6) ; 0,75 ; 0,8 ; 0,8(3)

0,(6)=6/9=2/3

0,75=75/100=3/4

0,8=8/10=4/5

0,8(3)=(83-8)/90=75/90=5/6

a+b+c+d=3804

{a;b;c;d} i.p.{2/3; 3/4; 4/5; 5/6}

2a/3=3b/4=4c/5=5d/6=k

a=3k/2; b=4k/3; c=5k/4; d=6k/5

=>3k/2 +4k/3 +5k/4 +6k/5=3804; aducem la acelasi numitor; 60

90k+80k+75k+72k=3804•60

317k=3804•60

k=3804•60/317=12•60=720

a=3•720/2=1080

b=4•720/3=960

c=5•720/4=900

d=6•720/5=864

(a;b;c;d)={(1080; 960; 900; 864)}