Question

impartiti nr.900 in parti direct proportionale cu nr.3 ;5, si 7

Answer 1

Fie {a, b, c} d.p. {3, 5, 7}

=> a/3=b/5=c/7=k

=> a=3k, b=5k si c=7k

a+b+c=900

3k+5k+7k=900

15k=900 |:15

k=60 => a=3*60=180

=> b=5*60=300

=> c=7*60=420

Deci 900 impartit in parti direct proportionale cu 3, 5 si 7 este: 900=180+300+420