Question

Impartiti numarul 106 in parti direct proportionale cu 0,(3) ; 2 si 1,2

Answer 1

0,(3)=3/9=1/3
x=k/3
y=2k
z=1,2k
x+y+z=106
k/3+2k+1,2k=106
k+6k+3,6k=318
10,6k=318
k=30
x=k/3=30/3=10
y=2k=2*30=60
z=1,2k=1,2*30=36