Question

Impartiti numarul 111 in 3 parti invers proportionale cu 3, 1/2, 4/3

Answer 1

a+b+c=111
a×3=b×1/2=c×4/3=k
a=k/3
b/2=k ⇒b=2k
4c/3=k ⇒c=3k/4
k/3+2k+3k/4=111
4k+12×2k+3×3k=111×12
4k+24k+9k=1332
37k=1332
k=1332÷37
k=36
a=36÷3
a=12
b=2×36
b=72
c=3×36/4
c=3×9
c=27