Question

Impartiti numarul 7 in parti invers proportionale cu numerele 2;3; 0,5 si 0,(3) .

Answer 1

x/(1/2) = y/(1/3) = z/2  = t/9 = 7/(1/2 + 1/3 + 11) = 7/(71/6) = 42/71
2x = 42/71      x = 21/71      y = 14/71    z = 84/71    t = 378/71

Answer 2

 [tex]0,5=\frac{1}{2}\;\;;\;\;0,(3)=\frac{3}{9}=\frac{1}{3}\,....\\
\Rightarrow\;\;\frac{a}{1/2}=\frac{b}{1/3}=\frac{c}{2}=\frac{d}{3}=\frac{7}{35/6}=35/6\\ \rightarrow\;\;a=6/5*1/2=6/10=3/5\;;\;b=6/5*1/3=6/15=2/5\;;\\
c=2*6/5=12/5\;si\;d=3*6/5=18/5\;;\\ [/tex]
deci:  a=3/5 
          b=2/5
          c=12/5
          d=18/5          ⇒   Verificare:  (3+2+12+18)/5=35/5=7