Question

Impartiti numarul 7 in parti invers proportionale cu numerele 2; 3; 0,5; 0,(3)

Answer 1

a+b+c+d=7
2a=3b=0,5c=0,(3)d=k
a=k/2=3/5
b=k/3=2/5
c=2k=12/5
d=3k=18/5
k/2+k/3+2k+3k=7
k(1/2+1/3+2+3)=7
k·35/6=7
k=6/5