Question

impartiti numarul 790 in parti invers proportionale cu numerele 3,5,8

Answer 1

x/1/3=y/1/5=z/1/8=>3X=5Y=8Z
3X=5Y=8Z=K
3X=K=>X=K/3
5Y=K=>Y=K/5
8Z=K=>Z=K/8
X+Y+Z=790
K/3+K/5+K/8=790 ADUCEM LA ACELASI NUMITOR  120
40K+24K+15K TOTUL IMPARTIT LA 120=790
79K=790X120
79K=94800
K= 94.800/79
K=1200
X= K/3=>X= 1200/3=> X=400
Y=1200/5 =>Y=240
Z=1200/8=150
X=400,Y=240,Z=150