Question

in 3 pungi erau 165 de nuci.cand din fiecare punga s a scos acelasi numar de nuci in prima punga au ramas 41 de nuci.in a doua 50 de nuci iar in a treia 35 de nuci. cate nuci au fost la inceput in fiecare punga

Answer 1

a+b+c=165
a-x=41
b-x=50
c-x=35
a+b+c-3x=41+50+35
165-3x=126
3x=39
x=13
a=41+x=41+13=54 nuci
b=50+x=50+13=63 nuci
c=35+x=35+13=48 nuci