Question

In ce cantitate de CuCl2 se va gasi aceeasi masa de clor ca in 4 moli de HCl?

Answer 1

M(HCl)=1+35.5=36.5

1mol HCl are.............36.5 g HCl..........35.5g Cl
4 moli....................................................x
x=4*35.5=142g Cl

M(CuCl2)=64+2*35.5=135

1mol CuCl2................135g CuCl2............2*35.5=71g Cl
                                     y............................142g
y=135*142/71=270g CuCl2 vor contine aceeasi masa de Cl ca 4 moli de HCl