Question

In ce cantitati de NH3 si CH4 se gaseste aceeasi cantitate de H ca in 12 moli H2O?

Answer 1

Trebuie sa afli cantitatea de H continuta in 12 moli apa
1mol H2O contine 2 g H
12 moli contin X
X=12x2=24 gH
MNH3=14+3=17g/mol
17 gNH3 contin 3 g H
Yg contin 24g H
Y=24x17/3=136 gNH3
M CH4=12+4=16g/mol
16g CH4 contin 4g H
Z g contin   24 gH
Z=24x16/4=96 gCH4