Question

in dreptunghiul ABCD.AC П BD=[0]iar m(< AOD)=60 gr. si AD=6 cm.Calculati Ac+BD..va rog mult.

Answer 1

$ABCD-dreptunghi \Rightarrow AC=BD \Rightarrow AO=BO=CO=DO \Rightarrow \\ \\ \Rightarrow \Delta AOD -isoscel,~dar~ m(\ \textless \ AOD)=60 \textdegree \Rightarrow \Delta AOD-echilateral \Rightarrow \\ \\ \Rightarrow AO=DO=AD=6~(cm). \\ \\ AO=BO=CO=DO=6~cm. \\ \\ AC+BD=(AO+CO)+(BO+DO)=(6+6)+(6+6)=24~(cm).$