Question

in paralelogramul ABCD AB=8 CM AD=6cm sin A=1/12.Aflati distanta dintre dreptele AB si CD.aflati distanta de la O la BC unde {O}=AC intersectat BD

Answer 1

Facem inaltimea DZ pe latura AB.  SinA=$\frac{ZD}{AD}$=$\frac{1}{12}$
$\frac{ZD}{6}$=$\frac{1}{12}$=> ZD=$\frac{6X1}{12}$=0,5cm