Question

in reperul cartezian se considera punctele A( 5,-1) ; B( 2,3) .Calcualti lungimea segmentului AB

Answer 1

$AB= \sqrt{( x_{2}- x_{1})^2 +( y_{2}- y_{1})^2 }= \sqrt{(2-5)^2+(3+1)^2} = \sqrt{9+16}=5$

Answer 2

$AB= \sqrt{(xB-xA)^{2}+ (yB-yA)^{2}}$
$AB= \sqrt{(2-5)^{2}+ (3+1)^{2}} =\sqrt{(-3)^{2}+ (4)^{2}}= \sqrt{25} =5 cm$