Question

In reperul cartezian xOy se considera punctele A(1,3) si B(-1,1).Determinati ecuatia dreptei AB 
(aratati si formula)

Answer 1

$\frac{x-xA}{xB-xA} = \frac{y-yA}{yB-yA}$

[tex] \frac{x-1}{-1-1} = \frac{y-3}{1-3} [/tex]

x-1/-2=y-3/-2
x-1=y-3
y=x+2

Answer 2

AB=x-xA supra xB-xA = y-yA supra yB-yA   - asta e formula