Question

In trapezul isoscel ABCD, AB=CD=4cm, AD=4 supra 5×BC=8cm. Perimetrul trapezul este egal cu:
a)16cm
b)24cm
c)26cm
d)20cm
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Answer 1

Răspuns: $\bf Perimetrul_{ABCD}= 26~cm$

Explicație pas cu pas:

Salutare!

Trapezul isoscel ABCD

$\bf AB = CD = 4~cm$

$\bf AD - baza~mica$

$\bf BC - baza~mare$

$\bf AD = 8\:cm \: (baza \: mica)$

$\bf AD = \dfrac{4}{5}\cdot BC = 8~cm$

$\bf \dfrac{4}{5}\cdot BC = 8~cm\:\Big|\cdot 5\implies 4\cdot BC=40\:\Big|:5\implies\boxed{\bf BC=10\:cm}$

$\bf Perimetrul_{ABCD}= AB+BC+CD+AD$

$\bf Perimetrul_{ABCD}= 4\:cm+10\:cm+4\:cm+8\:cm$

$\boxed{ \boxed {\bf Perimetrul_{ABCD}= 26~cm}}$

Varianta c) 26 cm

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