Question

in triunghiul abc avem ab=12 bc=8 si unghiu c=60 calculati sin a

Answer 1

   
[tex]\displaystyle\\ \text{Aplicam teorema sinusurilor.}\\\\ \frac{AB}{\sin C} = \frac{BC}{\sin A} \\\\\\ \frac{12}{\sin 60^o} = \frac{8}{\sin A} \\\\\\ \sin A = \frac{8\sin 60^0}{12}= \frac{2\sin 60^0}{3}=\frac{2}{3}\cdot\sin 60^0=\frac{2}{3}\cdot \frac{ \sqrt{3} }{2} =\boxed{\frac{ \sqrt{3} }{3}}[/tex]